acemuzzy wrote:Right, before the proof, somebody asked for a noddy explanation of all this shizzle (i, e, pi, euler's identity, complex numbers). So, feeling brave, I'm giong to try. Indulge me. And ask questions...
Let's start with i. i is kinda useless by itself. i only becomes useful if you square it. In fact, that's how it's defined - the thing that if you square it you get -1.
So, what is i? Well, doesn't really mean much till you square it.
But, if you then start doing maths with it, fun stuff happens.
Like, what's (2i) squared? Well that's (2i)^2 = (2*i)^2, and you can multiply out, so = (2^2) x (i^2) = 4 * i^2, and i^2 = -1, so that's -4. Whoop.
But then, more fun things happen. Like, what are the solution to x^2-2x+2=0? (i.e. the values of x for which that formula holds true; it doesn't for x=1 say, as that's 1^2-2x1+2 = 1-2+2 = 1, not 0).
You may remember the formula, x=(-b +/- sqrt(b^2-4ac)/2a. Let's try it.
x = (-(-2) +/- sqrt((-2)^2-4x1*2))/2x1
= (2 +/- sqrt(4 - 8 ))/2
= (2 +/- sqrt (-4))/2
oh wait, we just decided that sqrt(-4) = 2i.
So
x = (2 +/- 2i) / 2 = (1 +/- i)
Nice.
Let's test it (with (1 + i)).
x^2-2x+2 = (1+i)^2 - 2x(1+i) + 2
= (1^2 + 2i + i^2) - 2(1+i) + 2
= (1 + 2i - 1) - 2 - 2i + 2
= 0 as everything cancels.
Whoopitydoop.
More to follow....
voices wrote:Ah, didn't mean to be harsh. I was expecting a formal proof is all, and I guess I'm a maths fan/nerd.
Now, this might be me miss understanding, but I think the intermediate value theorem is different to the theory we were considering. The intermediate value theorem doesn't consider the location of the point, but we were looking at a point exactly half a rotation round from an exactly similarly temperature point.
Just to be clear, I'm happy to be wrong!
Actually, reconsidering, I think I get the graph now. Ha.... Weirdly enough I drew something similar on the way to my proof.... The key is that it's comparing the plus a half line, so the point of intersection is the one point we want.
Still not a formal proof though so ner!
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